Question on: WAEC Physics - 2009
A cell of e.m.f. 1.5V is connected in series with a resistor of resistance 3.0(\Omega). A voltmeter connected across the cell registers 0.9V. Calculate the internal resistance of the cell
A
2.0\(\Omega\).
B
3.0\(\Omega\).
C
5.0\(\Omega\).
D
6.0\(\Omega\).
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Correct Option: A
(\frac{V}{R} = \frac{E}{R + r})
(\frac{0.9}{3} = \frac{1.5}{3 + r})
r = 2(\Omega).
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